We
are bounded in a nutshell of Infinite space:
Blog Post #26, Worksheet # 8.1, Problem #1: Introduction to growth in infinite
directions
1. Before we dive
into the Hubble Flow, let’s do a thought experiment. Pretend that there is an
infinitely long series of balls sitting in a row. Imagine that during a time
interval \(\Delta
t\) the space between
each ball increases by \(\Delta
x\).
(a) Look at the
shaded ball, Ball C, in the figure above. Imagine that Ball C is sitting still
(so we are in the reference frame of Ball C). What is the distance to Ball D
after time \(\Delta
t\)? What about
Ball B?
(b) What are the
distances from Ball C to Ball A and Ball E?
(c) Write a
general expression for the distance to a ball N balls away from Ball C after
time \(\Delta t\). Interpret your
finding.
(d) Write the
velocity of a ball N balls away from Ball C during \(\Delta t\). Interpret your finding.
(a) As Edwin Hubble trained his
telescope onto the greater heavens, objects thousands if not hundreds of
thousands of light years away, he began to see the hints of something in play
in the universe, something few had ever thought of conceiving as possible.
Since ancient times, the Earth was the center of the cosmos, with everything
rotating around it, an idea disproven during the Scientific Revolution. But
even these great minds did not envision how humanity would later understand how
there were galaxies and clusters and unimaginably large structures in the
cosmos which left Hubble with a clear idea: the universe was growing, every
second, of every day. The expansion Hubble saw can be described by various
methods, mainly by his own Hubble Constant, but more on that in the next post.
First let us discuss how this
expansion works, how objects that are spaced from each other all move at a same
speed, but because of their original place, they continually look farther and
farther away.
In the example of a row of balls,
we have the question of how much distance separates B and D from C, in its
point of view. For each case, the distance to B or D is \(\Delta x\), as is
established by the question after a time \(\Delta t\).
(b) The same reasoning applies to
balls A and E, where if the space from B to A has to be \(\Delta x\) and if the
distance from C to B is already \(\Delta x\), then the distance from C to A has
to be \(2 \Delta x\), a case identical to ball E.
(c) So, if the balls’ position away
from the point of reference is the guiding force driving the distance it has
after a time \(\Delta t\), a ball N balls away will always be \(N
\Delta x\) away after a time \(\Delta t\). So the equation for the distance
from the ball C will always be: \[D(\Delta t) = N\Delta x .\] This shows, and
we’ll get more into this in just a bit, that the farther an object was at the
start, the farther it will move after a time \(\Delta t\)
(d) Now that we have a general
equation for the distance from the point of reference, we can use it to find
the velocity of the object for any original condition. From kinematics we
already know the equation for distance traveled by an object with constant
velocity is: \[X_f = X_i + v(\Delta t) ,\] which can be rewritten as: \[ v = \frac{X_f
– X_i }{\Delta t} ,\] \[ v = \frac{\Delta x}{\Delta t}, \] which happens to be
very similar to the equation for distance we have already found. Now we simply
plug in the actual distance equation for the case of a constant expansion as we
have been describing: \[v = \frac{N \Delta x}{\Delta t}, \] which describes the
velocity of an object we are viewing from a particular reference point. From
it, we can clearly see that an object that is farther away is perceived to be
moving increasingly faster, a fact which has helped astronomers many times.
As we will see in the next post,
apparent and actual velocities help a great deal, permitting us to understand
just how far away an object is (giving us a new rung on the distance ladder to
use as necessary), as well as how long its light has been traveling, but more
on this next time.
Rock on kinematics!
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